Tricky Methods for solve Average Related Questions

Dear Frnds Last article related to How solve Age Related problems, Now we find how solve Average Questions Quickly …… We know that …               Sum of Quantities Average =—————————                Number of Quantities Consecutive Numbers =x,x+1,x+2,X+3…….. ODD/EVEN Consecutive no.are-=x,X+2,x+4,x+6,x+8…… Q. If five consecutive no.average is 28 then find highest no.this series. Solution :       Number of this series –5      Average of this series –28                       5/2=2.5It means series middle no …28                            |                26,27,28,29,30So highest no. is- 30(‘-‘) Q2. If average of 8 ODD consecutive no. is 18 then find least no of this series. Solution –                     No.-8           Average -18Series. Odd- …

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Shortcuts for AGE Related Problems

Dear Frnds Mostly a question always ask related AGE……. So we discuss how solve Age related problem in minimum time with accuracy. When Current Age Ratio Know Q.The Ratio of age of Ram And Manoj 2:1 after 5 years the age ratio become 3:2. Find Both current age. Solution : First  Under line for time(After /Before)                            R.             MCurrent age.     2.               1+5 years.           3.      _       2                               Diff=1 Current age and +5 years ratio diff2=1(2-3)and (1-2) Note: Here both difference Is equal 1.                   5(time)×2(Ratio) *Diff1Current age Ram= -——————                                   Diff2                   Ram=5×2                          =10years                 Manoj=5×1                           =5years CASE 2: IF …

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How Make Simplification Easy

Dear Frnds We already discuss Easy calculations Tricks, Now understand how solve questions in examination related Simplificaton— BO-DMAS Rules B- Brackets in order (){}[] O- OF D- DIVISION M- MULTIPLICATION A- ADDITION S- SUBSTRACTION Example — 1÷[1+1÷{1+1÷(1+1÷3)}] Solution – Step1-(1+1÷3)=(1+1/3) Stet2- {1+1÷(1+1÷3)}={1+1÷4/3}                                  ={1+1×3/4}                                  ={1+3/4}                                  ={7/4} Step3-  [1+1÷{1+1÷(1+1÷3)}]            = [1+1÷{7/4}]            = [1+1÷7/4]           = [1+1×4/7]            =[1+4/7]             =[11/7]Step 4- 1÷[1+1÷{1+1÷(1+1÷3)}] =1÷[11/7]=1×7/11=7/11(‘-‘) Others Example : Q2- 888×88×8Solution – 888×88×8=8*111×8*11×8*1                =8³×111*11                 =512×1221                  =625152(‘-‘) Trick -If numbers increase or decrease in a sequence then- Highest numbers total digit count- here 3 Now number of digit -here 8 Now we find . 8³ and write 111(3digit)×11(decrease …

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